By xi’an

**R – Xi’an’s Og**, and kindly contributed to R-bloggers)

**W**hile the Riddler puzzle this week was anticlimactic, as it meant filling all digits in the above division towards a null remainder, it came as an interesting illustration of how different division is taught in the US versus France: when I saw the picture above, I had to go and check an American primary school on-line introduction to division, since the way I was taught in France is something like that

with the solution being that 12128316 = 124 x 97809… Solved by a dumb R exploration of all constraints:

for (y in 111:143) for (z4 in 8:9) for (oz in 0:999){ z=oz+7e3+z4*1e4 x=y*z digx=digits(x) digz=digits(z) if ((digz[2]==0)&(x>=1e7)&(x=1e3)&(digz[4]*y9)&(r1=1e2)&(7*y=1e2)&(r2=1e2)&(digz[3]*y9)&(r3Looking for a computer-free resolution, the constraints on z exhibited by the picture are that (a) the second digit is 0 and the fourth digit is 7. Moreover, the first and fifth digits are larger than 7 since y times this digit is a four-digit number. Better, since the second subtraction from a three-digit number by 7y returns a three-digit number and the third subtraction from a four-digit number by ny returns a two-digit number, n is larger than 7 but less than the first and fifth digits. Ergo, z is necessarily 97809. Furthermore, 8y

Filed under: Books, Kids, pictures, R Tagged: arithmetics, division, FiveThirtyEight, long division, The Riddler

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